Integrand size = 29, antiderivative size = 95 \[ \int \frac {\cos ^5(c+d x) \cot ^2(c+d x)}{a+a \sin (c+d x)} \, dx=-\frac {\csc (c+d x)}{a d}-\frac {\log (\sin (c+d x))}{a d}-\frac {2 \sin (c+d x)}{a d}+\frac {\sin ^2(c+d x)}{a d}+\frac {\sin ^3(c+d x)}{3 a d}-\frac {\sin ^4(c+d x)}{4 a d} \]
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Time = 0.10 (sec) , antiderivative size = 95, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.103, Rules used = {2915, 12, 90} \[ \int \frac {\cos ^5(c+d x) \cot ^2(c+d x)}{a+a \sin (c+d x)} \, dx=-\frac {\sin ^4(c+d x)}{4 a d}+\frac {\sin ^3(c+d x)}{3 a d}+\frac {\sin ^2(c+d x)}{a d}-\frac {2 \sin (c+d x)}{a d}-\frac {\csc (c+d x)}{a d}-\frac {\log (\sin (c+d x))}{a d} \]
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Rule 12
Rule 90
Rule 2915
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {a^2 (a-x)^3 (a+x)^2}{x^2} \, dx,x,a \sin (c+d x)\right )}{a^7 d} \\ & = \frac {\text {Subst}\left (\int \frac {(a-x)^3 (a+x)^2}{x^2} \, dx,x,a \sin (c+d x)\right )}{a^5 d} \\ & = \frac {\text {Subst}\left (\int \left (-2 a^3+\frac {a^5}{x^2}-\frac {a^4}{x}+2 a^2 x+a x^2-x^3\right ) \, dx,x,a \sin (c+d x)\right )}{a^5 d} \\ & = -\frac {\csc (c+d x)}{a d}-\frac {\log (\sin (c+d x))}{a d}-\frac {2 \sin (c+d x)}{a d}+\frac {\sin ^2(c+d x)}{a d}+\frac {\sin ^3(c+d x)}{3 a d}-\frac {\sin ^4(c+d x)}{4 a d} \\ \end{align*}
Time = 0.09 (sec) , antiderivative size = 66, normalized size of antiderivative = 0.69 \[ \int \frac {\cos ^5(c+d x) \cot ^2(c+d x)}{a+a \sin (c+d x)} \, dx=-\frac {12 \csc (c+d x)+12 \log (\sin (c+d x))+24 \sin (c+d x)-12 \sin ^2(c+d x)-4 \sin ^3(c+d x)+3 \sin ^4(c+d x)}{12 a d} \]
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Time = 0.34 (sec) , antiderivative size = 63, normalized size of antiderivative = 0.66
method | result | size |
derivativedivides | \(-\frac {\frac {\left (\sin ^{4}\left (d x +c \right )\right )}{4}-\frac {\left (\sin ^{3}\left (d x +c \right )\right )}{3}-\left (\sin ^{2}\left (d x +c \right )\right )+2 \sin \left (d x +c \right )+\ln \left (\sin \left (d x +c \right )\right )+\frac {1}{\sin \left (d x +c \right )}}{d a}\) | \(63\) |
default | \(-\frac {\frac {\left (\sin ^{4}\left (d x +c \right )\right )}{4}-\frac {\left (\sin ^{3}\left (d x +c \right )\right )}{3}-\left (\sin ^{2}\left (d x +c \right )\right )+2 \sin \left (d x +c \right )+\ln \left (\sin \left (d x +c \right )\right )+\frac {1}{\sin \left (d x +c \right )}}{d a}\) | \(63\) |
parallelrisch | \(\frac {39+96 \ln \left (\sec ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-96 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )+8 \left (-22+23 \cos \left (d x +c \right )-2 \cos \left (2 d x +2 c \right )+\cos \left (3 d x +3 c \right )\right ) \cot \left (\frac {d x}{2}+\frac {c}{2}\right )-48 \sec \left (\frac {d x}{2}+\frac {c}{2}\right ) \csc \left (\frac {d x}{2}+\frac {c}{2}\right )-36 \cos \left (2 d x +2 c \right )-3 \cos \left (4 d x +4 c \right )}{96 d a}\) | \(120\) |
risch | \(\frac {i x}{a}-\frac {3 \,{\mathrm e}^{2 i \left (d x +c \right )}}{16 a d}+\frac {7 i {\mathrm e}^{i \left (d x +c \right )}}{8 d a}-\frac {7 i {\mathrm e}^{-i \left (d x +c \right )}}{8 d a}-\frac {3 \,{\mathrm e}^{-2 i \left (d x +c \right )}}{16 a d}+\frac {2 i c}{a d}-\frac {2 i {\mathrm e}^{i \left (d x +c \right )}}{d a \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )}-\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )}{d a}-\frac {\cos \left (4 d x +4 c \right )}{32 a d}-\frac {\sin \left (3 d x +3 c \right )}{12 d a}\) | \(174\) |
norman | \(\frac {-\frac {1}{2 a d}-\frac {\tan ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )}{2 d a}-\frac {13 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d a}-\frac {13 \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d a}-\frac {\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )}{2 d a}-\frac {\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )}{2 d a}-\frac {43 \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d a}-\frac {43 \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d a}-\frac {47 \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d a}-\frac {47 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d a}-\frac {47 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{6 d a}-\frac {47 \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{6 d a}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{5} \tan \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}+\frac {\ln \left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a d}-\frac {\ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a d}\) | \(299\) |
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Time = 0.28 (sec) , antiderivative size = 85, normalized size of antiderivative = 0.89 \[ \int \frac {\cos ^5(c+d x) \cot ^2(c+d x)}{a+a \sin (c+d x)} \, dx=\frac {32 \, \cos \left (d x + c\right )^{4} + 128 \, \cos \left (d x + c\right )^{2} - 3 \, {\left (8 \, \cos \left (d x + c\right )^{4} + 16 \, \cos \left (d x + c\right )^{2} - 11\right )} \sin \left (d x + c\right ) - 96 \, \log \left (\frac {1}{2} \, \sin \left (d x + c\right )\right ) \sin \left (d x + c\right ) - 256}{96 \, a d \sin \left (d x + c\right )} \]
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Timed out. \[ \int \frac {\cos ^5(c+d x) \cot ^2(c+d x)}{a+a \sin (c+d x)} \, dx=\text {Timed out} \]
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Time = 0.22 (sec) , antiderivative size = 74, normalized size of antiderivative = 0.78 \[ \int \frac {\cos ^5(c+d x) \cot ^2(c+d x)}{a+a \sin (c+d x)} \, dx=-\frac {\frac {3 \, \sin \left (d x + c\right )^{4} - 4 \, \sin \left (d x + c\right )^{3} - 12 \, \sin \left (d x + c\right )^{2} + 24 \, \sin \left (d x + c\right )}{a} + \frac {12 \, \log \left (\sin \left (d x + c\right )\right )}{a} + \frac {12}{a \sin \left (d x + c\right )}}{12 \, d} \]
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Time = 0.32 (sec) , antiderivative size = 95, normalized size of antiderivative = 1.00 \[ \int \frac {\cos ^5(c+d x) \cot ^2(c+d x)}{a+a \sin (c+d x)} \, dx=-\frac {\frac {12 \, \log \left ({\left | \sin \left (d x + c\right ) \right |}\right )}{a} - \frac {12 \, {\left (\sin \left (d x + c\right ) - 1\right )}}{a \sin \left (d x + c\right )} + \frac {3 \, a^{3} \sin \left (d x + c\right )^{4} - 4 \, a^{3} \sin \left (d x + c\right )^{3} - 12 \, a^{3} \sin \left (d x + c\right )^{2} + 24 \, a^{3} \sin \left (d x + c\right )}{a^{4}}}{12 \, d} \]
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Time = 10.72 (sec) , antiderivative size = 272, normalized size of antiderivative = 2.86 \[ \int \frac {\cos ^5(c+d x) \cot ^2(c+d x)}{a+a \sin (c+d x)} \, dx=\frac {4\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{a\,d}-\frac {8\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4}{a\,d}+\frac {8\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6}{a\,d}-\frac {4\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8}{a\,d}+\frac {\ln \left (\frac {1}{{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}\right )}{a\,d}-\frac {\ln \left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}\right )}{a\,d}+\frac {20\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3}{3\,a\,d\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}-\frac {16\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5}{3\,a\,d\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}+\frac {8\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7}{3\,a\,d\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}-\frac {9\,\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}{2\,a\,d\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}-\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}{2\,a\,d\,\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )} \]
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